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Q.

Alternating current in circuit is given by I = I₀ $\sin 2 πnt$ Then the time taken by the current to rise from zero to r.m.s. value is equal to

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a

$\frac{1}{2 n}$

b

$\frac{1}{n}$

c

$\frac{1}{4 n}$

d

$\frac{1}{8 n}$

answer is D.

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Detailed Solution

$I = I_{0} Sin 2 πnt$

$\frac{I_{0}}{\sqrt{2}} = I_{0} \sin 2 πnt$

$\frac{1}{\sqrt{2}} = \sin 2 πnt \Rightarrow 2 πnt = \frac{π}{4}$

$t = \frac{1}{8 n}$

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