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Aluminium chloride exits as a dimer, ${Al}_{2} {Cl}_{6}$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives:

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${[Al (OH)_{6}]}^{3 -} + 3 HCl$

${Al}^{3 +} + 3 {Cl}^{⊖}$

${Al}_{2} O_{3} + 6 HCl$

${[Al {(H_{2} O)}_{6}]}^{3 +} + 3 {Cl}^{⊖}$

answer is C.

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Detailed Solution

The dimeric form ${Al}_{2} {Cl}_{6}$ is retained in non-polar solvent but is broken into $∣ [Al {(H_{2} O)}_{6}] {Cl}_{3}$ on dissolution in water due to high heat of hydration.

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