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Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining $Al / {Al}^{3 +} and Ag / {Ag}^{+}$ is 2.46 V. The reduction potential of silver electrode is + 0.80 V. The reduction potential of aluminium electrode is

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– 3.26 V

– 1.66 V

+ 1.66 V

+ 3.26 V

answer is D.

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Detailed Solution

$A l | A l^{3 +} | | A g^{+} | A g E_{c e l l}^{o} = E_{A g^{+} / A g}^{o} - E_{A l^{3 +} / A l}^{o} 2.46 = 0.80 - E_{A l^{3 +} / A l}^{o} E_{A l^{3 +} / A l}^{o} = - 1.66 V$

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