Aluminium reacts with hydrogen chloride to produce H2 according to the equation 2Al + 6HCl → 2AlCl3 + 3H2 Then 2grams of H2 would be produced from

2Al +6 HCl → 2 AlCl3 + 3 H22 moles 3 (2g) ‘X’ moles 2gX =2 x 23 x 2=23moles

2Al +6 HCl → 2 AlCl3 + 3 H22 moles 3 (2g) ‘X’ moles 2gX =2 x 23 x 2=23moles

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Aluminium reacts with hydrogen chloride to produce H₂ according to the equation 2Al + 6HCl → 2AlCl₃ + 3H₂Then 2grams of H₂ would be produced from

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2 moles of Al

1 mole of Al

2/3 mole of Al

3/2 mole of Al

answer is C.

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2Al +6 HCl $\to$ 2 AlCl₃ + 3 H₂

2 moles 3 (2g)

‘X’ moles 2g
X = $\frac{2 x 2}{3 x 2} = \frac{2}{3}$ moles

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