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Aluminium reacts with NaOH and forms compound 'X'. If the coordination number of aluminium in 'X' is 6, the correct formula of X is

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[Al(H₂O)₂(OH)₄]^–

[Al(H₂O)₃(OH)₃]

[Al(H₂O)₆(OH)₃]

[Al(H₂O)₄(OH)₂]⁺

answer is A.

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Detailed Solution

$2 A l + 2 N a O H 2 H_{2} O \overset{}{\to} 2 N a A l O_{2} + 3 H_{2}$

The sodium meta aluminate, thus formed , is soluble in water and changes in to a complex $N a [A l {(H_{2} O)}_{2} {(O H)}_{4}]$ in which the coordination number of Al is '6'.

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