Aman walks horizontally in rain with a velocity of 5 m/s. The raindrops strike on his back at angle of 45⁰ with the horizontal. Then for the actual rain's velocity

Velocity of man: $\overrightarrow{v_m}=5\widehat{i}$

Velocity of rain w.r.t man:

${\overrightarrow{v_{ }}}_{r/m}=v_1\cos {45}^{\circ }\widehat{i}-v_1\sin {45}^{\circ }\widehat{k}=\frac{v_1}{\sqrt{2}}\widehat{i}-\frac{v_1}{\sqrt{2}}\widehat{k}$

Hence, velocity of rain:

$\begin{array}{l}\overrightarrow{v_r}={\overrightarrow{v}}_{r/m}+\overrightarrow{v_m}\\ \Rightarrow \overrightarrow{v_r}=\left(\frac{v_1}{\sqrt{2}}+5\right)\widehat{i}-\frac{v_1}{\sqrt{2}}\widehat{k}\end{array}$

Horizontal component of rain's velocity $=\frac{v_1}{\sqrt{2}}+5$

Vertical component of rain's velocity $=\frac{v_1}{\sqrt{2}}$

So horizontal component > vertical component