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Q.

Ammonium hydrogen sulphide dissociates according to the equation :
${NH}_{4} HS (s) ⇌ {NH}_{3} (g) + H_{2} S (g)$
The total pressure at equilibrium at 400K is found to be 1atm. The equilibrium constant $K_{p}$ of the reaction is :

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a

$1 {atm}^{2}$

b

$0.5 atm$

c

$0.25 {atm}^{2}$

d

$0.25 atm$

answer is B.

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Detailed Solution

$K_{p}$ for the given reaction;

${NH}_{4} HS (s) ⇌ {NH}_{3} (g) + H_{2} S (g)$

$P_{{NH}_{3}} = P_{H_{2} S} = 0.5;$

$K_{P} = {0.5}^{2}$

$K_{P} = 0.25$

Thus, $K_{p}$ of the reaction is 0.25 atm².

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Ammonium hydrogen sulphide dissociates according to the equation :NH4HS(s)⇌NH3(g)+H2S(g)The total pressure at equilibrium at 400K is found to be 1atm. The equilibrium constant Kp of the reaction is :