Among the following, the possible length of sides of a right angled triangle are

From Pythagoras theorem :

A) ${10}^2=6^2+8^2$

$100=36+64$

$100=100$

$6,8,10$  will from a rightangle ${\Delta }^{le}$

B)${11}^2=5^2+8^2$

$121=25+64$

$121\ne 89$

$\therefore$  $5,8,11$  will not forms a rightangle ${\Delta }^{le}$

C)${17}^2=8^2+{15}^2$

$289=64+225$

$289=289$

$\therefore$  $8,15,17$  will forms a rightangle ${\Delta }^{le}$

D)${25}^2=7^2+{24}^2$

$625=49+576$

$625=625$

$\therefore$  $7,24,25$  will form a rightangle ${\Delta }^{le}$