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Among 15 players,8 are batsmen and 7 are bowlers. The probability that a team is chosen of 6 batsmen and 5 bowlers, is

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$\frac{^{8} C_{6} \times^{7} C_{5}}{^{15} C_{11}}$

$\frac{^{8} C_{6} +^{7} C_{5}}{^{15} C_{11}}$

$\frac{15}{28}$

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Detailed Solution

Total number of ways of selecting 11 players $=^{15} C_{11}$
Favorable cases $=^{8} C_{6} \times^{7} C_{5}$
Required probability $= \frac{^{8} C_{6} \times^{7} C_{5}}{^{15} C_{11}}$

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