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Among $LiCl, {BeCl}_{2}, {BCl}_{3}$ and ${CCl}_{4}$ , the covalent bond character follows the order

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$LiCl < {BeCl}_{2} > {BCl}_{3} > {CCl}_{4}$

$LiCl > {BeCl}_{2} < {BCl}_{3} < {CCl}_{4}$

$LiCl < {BeCl}_{2} < {BCl}_{3} < {CCl}_{4}$

$LiCl > {BeCl}_{2} > {BCl}_{3} > {CCl}_{4}$

answer is C.

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Detailed Solution

Li, Be, B, and C are of the same period where the size decreases from left to right.
Lesser the size of the cation, the more the covalent character.
Hence, the covalent character increases from $LiCl < {BeCl}_{2} < {BCl}_{3} < {CCl}_{4}$ .

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