Among the compounds, ${\mathrm{BF}}_3,{\mathrm{NCl}}_3,{\mathrm{H}}_2\mathrm{S},{\mathrm{SF}}_4\mathrm{and}{\mathrm{BeCl}}_2,$ identify the ones in which the central atom has the same type of hybridization

In $NC{l}_{3}and{H}_{2}S$ the central atom of both (N and S) are in ${\mathrm{sp}}^3\mathrm{hybridization}\mathrm{state}$

while in $B{F}_{3}andNC{l}_3$ central atoms are in $s{p}^{2}ands{p}^{3}hybridization$ respectively. In $H_{2}SandBeC{l}_2$ central atom are in $s{p}^{3}ands{p}^{2}hybridization$ In $B{F}_3,NC{l}_{3}and{H}_{2}S$ central atom are in $s{p}^2,s{p}^{3}ands{p}^{3}hybridization$ and in $NC{l}_{3}and{H}_{2}S$ the central atom are in $s{p}^{3}ands{p}^{3}hybridization.$