Among the first lines of Lyman, Balmer, Paschen and Brackett series in hydrogen atomic spectra, which has higher energy?

Energy is calculated as using the following expression:

$∆\mathrm{E}=13.6\left[\frac{1}{{\mathrm{n}}_1^2}-\frac{1}{{\mathrm{n}}_2^2}\right]$

For Lyman series, n₁=1 and n₂=2

$$\begin{gathered} ∆\mathrm{E}=13.6\left[\frac{1}{1^2}-\frac{1}{2^2}\right] \\ =10.2 \mathrm{eV} \end{gathered}$$

For Balmer series, n₁=2 and n₂=3

$∆\mathrm{E}=13.6\left[\frac{1}{2^2}-\frac{1}{3^2}\right]=1.88 \mathrm{eV}$

On moving further, the energy value decreases. Therefore, the highest energy corresponds to Lyman series.