Among the following, an correct statement is:

A metal pipe is 77 cm long.  The inner diameter of a cross-section is 4 cm.  The outer diameter is 4.4 cm.  Then the

C.S.A. inner of cylinder $=2\pi rh$

$=2\times \frac{22}{7}\times 2\times 77$

$=88\times 11$

$=968c{m}^2$  (A)

Outer surface area $=2\pi rh$

$r=\frac{d}{2}=\frac{4.4}{2}=2.2=\frac{22}{10}$

$=2\times \frac{22}{7}\times \frac{22}{10}\times 77$

$=\frac{22\times 22\times 22}{10}=\frac{10648}{10}=1064.8c{m}^2$ (B)

T.S.A. of cylinder $=$ Inner C.S.A. $+$ Outer C.S.A.$+2(\pi R^2-\pi r^2)$

$=968+1064.8+\frac{22}{7}({\left(2.2\right)}^2-{\left(2\right)}^2)\times 2$

$=2032.8+5.28$

$=2038.08c{m}^2$ (C)

Surface area of the end $=\pi R^2-\pi r^2$

$=\pi [{\left(2.2\right)}^2-{\left(2\right)}^2]$

$=\frac{22}{7}\times 4.2\times 0.2$

$=2.64c{m}^2$