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Among the following choices choose the correct option for a perfect square number having $n$ digits where $n$ is even will have square root with:

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n + 1

digit

n 2

digit

n 3

digit

n + 1 2

digit

answer is B.

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Detailed Solution

Let us consider a perfect square number with n digits, where n is even.
Consider 1296 which is a perfect square number with 4 digits, which is even.
Number of digits in 1296 = 4.
We know that the square root of 1296 is 36 which is a 2 digit number.

\sqrt{1296} = 36

4 digit square number have

\frac{4}{2} = 2

digit square root.
So, in general, for a perfect square number having n digits where n is even will have square root with

\frac{n}{2}

digits.
Hence, option 2 is correct.

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Among the following choices choose the correct option for a perfect square number having n digits where n is even will have square root with:

Detailed Solution

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Among the following choices choose the correct option for a perfect square number having $n$ digits where $n$ is even will have square root with: