Among the following compounds which does not have more than one type of hybridisation for carbon atoms?

$\mathrm{In} {\mathrm{CH}}_3–{\mathrm{CH}}_2-{\mathrm{CH}}_2–{\mathrm{CH}}_3$

All C atoms are sp² hybridised

$\mathrm{In} {\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}–{\mathrm{CH}}_3$

C atoms are sp³ and sp² hybridised

$\mathrm{In} {\mathrm{CH}}_2=\mathrm{CH}–\mathrm{C}\equiv \mathrm{CH}$

C atoms are sp² and sp hybridised

$\mathrm{In} \mathrm{H}–\mathrm{C}\equiv \mathrm{C}–{\mathrm{CH}}_3$

C atoms are sp³ and sp hybridised

Thus, ${\mathrm{CH}}_3–{\mathrm{CH}}_2-{\mathrm{CH}}_2–{\mathrm{CH}}_3$ has all C atoms of same hybridisation.

Hence, the correct option is option (A) ${\mathrm{CH}}_3–{\mathrm{CH}}_2-{\mathrm{CH}}_2–{\mathrm{CH}}_3$.