Among the following ethers which one will produce methyl alcohol on treatment with hot concentrated HI?

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${({CH}_{3})}_{2} {CHCH}_{2} - O - {CH}_{3}$

${CH}_{3} - {CH}_{2} - {CH}_{2} - {CH}_{2} - O - {CH}_{3}$

${({CH}_{3})}_{3} C - O - {CH}_{3}$

${CH}_{3} - {CH}_{2} - CH {({CH}_{3})}_{3} {CH}_{2} - O - {CH}_{3}$

answer is C.

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Detailed Solution

Given data : It is given to identify among the following ethers which one will produce methyl alcohol on treatment with hot concentrated HI

Explanation

t-Butyl iodide and methyl alcohol are formed when t-Butyl methyl ether reacts with hot concentrated HI acid.

Hence, the correct option D. ${({CH}_{3})}_{3} C - O - {CH}_{3}$

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