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Among the following series of transition metal ions, the one where all metal ions have same 3d electronic configuration is:

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${Ti}^{2 +}, V^{3 +}, {Cr}^{4 +}, {Mn}^{5 +}$

${Ti}^{3 +}, V^{2 +}, {Cr}^{3 +}, {Mn}^{4 +}$

${Ti}^{+}, V^{4 +}, {Cr}^{6 +}, {Mn}^{7 +}$

${Ti}^{4 +}, V^{3 +}, {Cr}^{2 +}, {Mn}^{3 +}$

answer is A.

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Detailed Solution

Ti⁺²,V³⁺,Cr⁺⁴,Mn⁺⁵ have 3d² configurations

Ti=[Ar]3d²4s²

Ti⁺²=[Ar]3d²

V=[Ar]3d³4s²

V⁺³=[Ar]3d²

Cr=[Ar]3d⁵4s¹

Cr⁺⁴=[Ar]3d²

Mn=[Ar]3d⁵4s²

Mn⁺⁵=[Ar]3d²

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