Among the following statements the one which is false in case of a particle moving in a circle with a constant angular velocity

$\overline{\omega }$=constant means U. C. M,

In U.C.M ${\text{a}}_{\text{T}}=0,{\text{a}}_{\text{N}}\ne 0$

Now we get the following are true

(i) Velocity vector is tangential to the circle.

(ii) In the case of uniform circular motions its acceleration vector always

towards its centre because

$a=\sqrt{{a_{\text{T}}}^2+{a_{\text{N}}}^2}$

$\therefore a=a_{\text{N}}$

(iii) The velocity and acceleration vectors are perpendicular to each other.

But acceleration vector do not remain tangential to the circle.

So among the given options option (B) is false