Among the following the compound that is both paramagnetic and coloured is

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(NH₄)₂[TiCl₆]

VOSO₄

K₂Cr₂O₇

K₃Cu(CN)₄

answer is C.

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Detailed Solution

In K₂Cr₂O₇, the oxidation state of Cr is +6 Cr⁺⁶=[Ar] 3d⁰
In (NH₄)₂[TiCl₆], the oxidation state of Ti is +4. Ti⁺⁴=[Ar] 3d⁰
In VOSO₄, the oxidation state of V is +4. V⁺⁴=[Ar] 3d¹
In K₃[Cu(CN)₄], the oxidation state of Cu is +1. Cu⁺¹=[Ar] 3d¹⁰
In VOSO₄, V⁺⁴ configuration is d¹, so it has one unpaired d-electron so it is paramagnetic and colored. All other compounds don't have any unpaired d electrons, so they are diamagnetic in nature.

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