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Q.

Among the following the compound that is both paramagnetic and coloured is

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a

(NH4)2[TiCl6]

b

VOSO4

c

K2Cr2O7

d

K3Cu(CN)4

answer is C.

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Detailed Solution

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  • In K2​Cr2​O7​, the oxidation state of Cr is +6            Cr+6=[Ar] 3d0
  • In (NH4​)2​[TiCl6​], the oxidation state of Ti is +4.  Ti+4=[Ar] 3d0
  • In VOSO4​, the oxidation state of V is +4.             V+4=[Ar] 3d1
  • In K3​[Cu(CN)4​], the oxidation state of Cu is +1.  Cu+1=[Ar] 3d10
    In VOSO4​, V+4 configuration is d1, so it has one unpaired d-electron so it is paramagnetic and colored. All other compounds don't have any unpaired d electrons, so they are diamagnetic in nature.
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