Among the following the equation whose roots are equal is

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$x^{2} + 6 x + 12 = 0$

$x^{2} - 8 x + 16 = 0$

$x^{2} + 3 x + 6$

$x^{2} - x + 1 = 0$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Option (A ): $x^{2} - x + 1 = 0 (a = 1, b = - 1, c = 1)$

$\begin{array}{l} Δ = b^{2} - 4 a c = {(- 1)}^{2} - 4 (1) (1) \\ = 1 - 4 \\ = - 3 \neq 0 \end{array}$

Option ( B ): $x^{2} + 3 x + 6 = 0 (a = 1, b = 3, c = - 6)$

$\begin{array}{l} Δ = b^{2} - 4 a c \\ = {(3)}^{2} - 4 (1) (+ 6) \\ = 9 - 24 \\ = - 15 \neq 0 \end{array}$

Option ( C ): $x^{2} - 8 x + 16 = 0$

$\begin{array}{l} a = 1, b = - 8, c = 16 \\ Δ = b^{2} - 4 a c \\ = {(- 8)}^{2} - 4 (1) (16) \\ = 64 - 64 \\ = 0 \end{array}$

Since $Δ = 0$ , it has equal roots

Option ( D): $x^{2} + 6 x + 12 = 0$

$\begin{array}{l} a = 1, b = 6, c = 12 \\ Δ = b^{2} - 4 a c \\ = {(6)}^{2} - 4 (1) (12) \\ = 36 - 48 \\ = - 12 \neq 0 \end{array}$

Watch 3-min video & get full concept clarity