Among the positive divisors of the number 12600 , if n1 is the number of divisors which are multiples of 3 and n2 is the number of divisors which are multiples of 14 , then n1+n2=

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Among the positive divisors of the number 12600 , if $n_{1}$ is the number of divisors which are multiples of 3 and $n_{2}$ is the number of divisors which are multiples of 14 , then $n_{1} + n_{2} =$

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answer is A.

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