Among the statements:

$\text{ (S1) }\left(\right(\mathrm{p}\vee \mathrm{q})\Rightarrow \mathrm{r})\iff (\mathrm{p}\Rightarrow \mathrm{r})$

$\left(\mathrm{S}2\right)\left(\right(\mathrm{p}\vee \mathrm{q})\Rightarrow \mathrm{r})\iff \left(\right(\mathrm{p}\Rightarrow \mathrm{r})\vee (\mathrm{q}\Rightarrow \mathrm{r}\left)\right)$

nether (S1) nor (S2) is a tautology

only (S1) is a tautology

both (S1) and (S2) are tautologies

only (S2) is a tautology