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Q.

Among the subsequent options, the roots of the equation x 2 +6x a 2 +2a8 =0 by applying the quadratic formula are


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a

a2,(a+4)

b

a+2,(a+4)

c

a2,(a4)

d

a+2,(a4)  

answer is A.

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Detailed Solution

The given quadratic equation is x 2 +6x a 2 +2a8 =0(1) .
We have to find the roots of the equation.
Compare equation (1) with the standard form a x 2 +bx+c=0.
a=1, b=6, c= a 2 +2a8
Find the determinant D by using the formula, D= b 2 4ac .
Substitute the known values in the formula.
D= b 2 4ac
D=62-4×1×(-(a2+2a-8))
D=36+4 a 2 +8a32
D=4 a 2 +8a+4 D=4( a 2 +2a+1) D=4 (a+1) 2
The formula gives the roots of the quadratic equation, b± D 2a .
Now,
D = 4 a+1 2 D =2 a+1
Substitute the known values to seek out the roots of the equation.
. α,β= b+ D 2a , b D 2a α,β = 6 +2(a+1) 2×1 , 6 2(a+1) 2×1
α,β = 6+2a+2 2 , 62a2 2
α,β =a2,(a+4)
Hence, the roots of the equation are a2,(a+4) .
Therefore, option 1) is correct.
 
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