Among $H_{2} O, H_{2} S, H_{2} Se$ and $H_{2} Te$ the one with the highest boiling point is

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$H_{2} S$ because of hydrogen bonding

$H_{2} Te$ because of highest molecular mass

$H_{2} O$ because of hydrogen bonding

$H_{2} Se$ because of lower molecular mass

answer is C.

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Detailed Solution

Among $H_{2} O, H_{2} S, H_{2} Se$ and $H_{2} Te$ , the one with the highest boiling point is $H_{2} O$ because of intermolecular hydrogen bonding which leads to molecular association and leads to higher energy for boiling.

Hence, the correct option is option (C) $H_{2} O$ because of hydrogen bonding.

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