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Q.

Amongst Ni(CO)4, [Ni(CN)4]2- and [NiCl4]2- :

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a

[NiCl4]2-  and [Ni(CN)4]2- are diamagnetic and Ni(CO)4 is paramagnetic
 

b

Ni(CO)4 and [Ni(CN)4]2- are diamagnetic and [NiCl4]2-  is paramagnetic
 

c

Ni(CO)4 is diamagnetic and [NiCl4]2-  and [Ni(CN)4]2- are paramagnetic

d

Ni(CO)4 and [NiCl4]2-  are diamagnetic and [Ni(CN)4]2- is paramagnetic

 

answer is C.

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Detailed Solution

  • When two atomic orbitals join to generate a hybrid orbital in a molecule, the energy of the individual atoms' orbitals is redistributed to give orbitals of equivalent energy. This method is known as hybridization.
  • Hybridization of [Ni(CO)4] is sp3 and [Ni(CN)4]2- is dsp3, since all the electrons are paired in both of these compounds they are diamagnetic while in[NiCl4]2-, Cl is a weak ligand and hence is unable to pair up all the electrons of 3d.

Hence, the correct option is option (C) Ni(CO)4 and [Ni(CN)4]2- are diamagnetic and [NiCl4]2-  is paramagnetic.

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