Amongst the elements with following electronic configurations, which one of them may have the highest ionization energy?

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$N e [3 s^{2} 3 p^{3}]$

$N e [3 s^{2} 3 p^{2}]$

$N e [3 s^{2} 3 p^{1}]$

$A r [3 d^{10} 4 s^{2} 4 p^{3}]$

answer is D.

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Detailed Solution

The smaller the atomic size, larger is the value of ionization potential. Further the atoms having half- filled or fully orbitals are comparatively more stable, hence more energy is required to remove the electron from such atoms.

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