Amongst the trihalides of nitrogen, which one is most basic?

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$N C l_{3}$

$N I_{3}$

$N B r_{3}$

$N F_{3}$

answer is D.

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Detailed Solution

$N F_{3} < N C l_{3} < N B r_{3} < N I_{3}$

• Nitrogen triiodide is the most basic in nature as iodine has the lowest electro negativity amongst halogens.
• Thus, the trend for the basicity in trihalides of nitrogen will be
$N F_{3} < N C l_{3} < N B r_{3} < N I_{3}$

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