Amongst ${\mathrm{FeCl}}_3.3{\mathrm{H}}_2\mathrm{O}, {\mathrm{K}}_3\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]$ and $\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_6\right]{\mathrm{Cl}}_3$, the spin-only magnetic moment value of the inner-orbital complex that absorbs light at shortest wavelength is __________B.M. [nearest integer]

$\left[\mathrm{Fe}{\left({\mathrm{H}}_2\mathrm{O}\right)}_3{\mathrm{Cl}}_3\right], \underset{\text{inner orbital complexes }}{\underbrace{{\mathrm{K}}_3\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right],\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_6\right]{\mathrm{Cl}}_3}}$

${\mathrm{K}}_3\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]\text{ has more }{\Delta }_0\text{ than }\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_6\right]{\mathrm{Cl}}_3;\text{ as }\overline{\mathrm{C}}\mathrm{N} \mathrm{is} \mathrm{stronger} \mathrm{ligand}.$

$\text{ More the }{\Delta }_0,lesser\text{ will be the value of absorbed }\lambda$

$\text{ Spin only magnetic moment }\left(\mathrm{\mu }\right)=\sqrt{3}\mathrm{BM}$

$=1.732\mathrm{BM} \text{ Rounding off }\Rightarrow 2$