Q.

Amonkey of mass 15kg is climbing on a rope with one end fixed to the ceiling. If it wishes to go up with an acceleration of 1m/s2, how much force should it apply to the rope ? If the rope is 5m long and the monkey starts from rest, how much time will it take to reach the ceiling ?

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a

165N, 10sec

b

132N, 10sec

c

153N, 10sec

d

120N, 10sec

answer is D.

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Detailed Solution

T − mg = ma

⇒T = m(g + a) = 15×11 = 165N

We know h = ut + 12at2

given h = 5m, u = 0, a = 1m/s2

t = 2ha

 = 10

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Amonkey of mass 15kg is climbing on a rope with one end fixed to the ceiling. If it wishes to go up with an acceleration of 1m/s2, how much force should it apply to the rope ? If the rope is 5m long and the monkey starts from rest, how much time will it take to reach the ceiling ?