Amount of electricity that can deposit 108 g of silver from ${AgNO}_{3}$ solution is

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1 coulomb

1 faraday

1 ampere

none of the above

answer is C.

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Detailed Solution

$\begin{array}{l} {Ag}^{+} + e^{-} \to Ag; E_{Ag} = \frac{Atomic mass}{1} = 108 \\ Number of Faraday= \frac{W_{Ag}}{E_{Ag}} = \frac{108}{108} = 1 \end{array}$

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