Amount of oxalic acid present in a solution can be determined by its titration with ${KMnO}_{4}$ solution in the presence of $H_{2} {SO}_{4}$ The titration gives unsatisfactory result when carried out in the presence of HCl because HCl

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

reduces permanganate to ${Mn}^{2 +}$

oxidises oxalic acid to carbon dioxide and water

gets oxidised by oxalic acid to chlorine

furnishes $H^{+}$ ions in addition to those from oxalic acid.

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The statement d is correct since the standard reduction potential of ${MnO}_{4}^{-}, {Mn}^{2 +}, H^{+} ∣ Pt$ is larger than that of ${Cl}^{-} |{Cl}_{2} (g)| Pt$ Thus, ${Cl}^{-}$ is oxidized to ${Cl}_{2}$ while ${MnO}_{4}^{-}$ is reduced to ${Mn}^{2 +}$