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Amount of oxalic acid present in a solution can be determined by its titration with ${KMnO}_{4}$ solution in the presence of $H_{2} {SO}_{4} .$ The titration gives unsatisfactory result when carried out in the presence of HCl because HCl

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gets oxidized by oxalic acid to chlorine

Furnishes $H^{+}$ ions in addition to those from oxalic acid

Reduces permanganate to ${Mn}^{2 +}$

Oxidises oxalic acid to carbon dioxide and water

answer is C.

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Detailed Solution

Titration of oxalic acid by ${KMnO}_{4}$ in the presence of HCl gives unsatisfactory result because HCl is a better reducing agent than oxalic acid and HCl reduces preferably ${MnO}_{4}^{-} to {Mn}^{2 +} .$

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