Amplitude modulated wave is represented by VAM=10[1+0.4cos(2π×104t)]cos(2π×107t).The total bandwidth of the amplitude modulated wave in kHz is:

ωm=2π×104fm=wm2π=104π=10KHz Band width = 2fm=2×10=20KHz

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Amplitude modulated wave is represented by $V_{A M} = 10 [1 + 0.4 \cos (2 π \times 10^{4} t)] \cos (2 π \times 10^{7} t) .$ The total bandwidth of the amplitude modulated wave in kHz is:

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answer is 20.

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$ω_{m} = 2 π \times 10^{4}$

$f_{m} = \frac{w_{m}}{2 π} = 10^{4} π = 10 KHz$

Band width = 2f_m

$= 2 \times 10 = 20 KHz$

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