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Q.

Amplitude of oscillation of a particle that executes SHM is 2 cm. Its displacement from its mean position in a time equal to1/6th of its time period is

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An Intiative by Sri Chaitanya

a

13cm

b

3cm

c

2cm

d

12cm

answer is B.

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Detailed Solution

y=Asin⁡2πTt y=2sin⁡2πT⋅T6=3

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