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An ice berg of density $900 k g / m^{3}$ is floating in water of density $1000 k g / m^{3}$ . The percentage of volume of ice cube out side the water is

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25%

20%

10%

35%

answer is C.

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Detailed Solution

$\frac{v_{o u t}}{v} \times 100 % = (1 - \frac{ρ_{i c e}}{ρ_{w a t e r}}) 100 % = (1 - \frac{0.9}{1}) 100 % = 10 %$

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