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An ideal heat engine working between temperature $T_{H}$ and $T_{L}$ has efficiency $η$ . If both the temperature are raised by $100 K$ each, the new efficiency of heat engine will be

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Greater than $η$

Greater or less than $η$ depending upon the nature of the working substance

Equal to $η$

Less than $η$

answer is C.

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Detailed Solution

$η_{1} = 1 - \frac{T_{2}}{T_{1}} η_{2} = 1 - \frac{T_{2} + 100}{T_{1} + 100}$

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