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Q.

An $α$ - particle collides with a stationary lithium, as $^{4} H e +^{7} L i \to^{10} B + n$ . If Q value of this reaction is $Q = - 2.5 M e V$ . Find the minimum value of kinetic energy of $α$ - particle required for the reaction?

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a

1.52 MeV

b

2.92 MeV

c

3.92 MeV

d

4.42 MeV

answer is D.

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Detailed Solution

$T h r e s h o l d e n e r g y = E_{t h} = - Q (1 + \frac{A_{α}}{A_{L i}}) = - (- 2.5) (1 + \frac{4}{7}) M e V \Rightarrow E_{t h} = 3.92 M e V$

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An α - particle collides with a stationary lithium, as 4He+7Li→10B+n . If Q value of this reaction is Q=−2.5MeV. Find the minimum value of kinetic energy of α- particle required for the reaction?