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Q.

An AC source rated 100 V (rms) supplies a current of 10A (rms) to a circuit. The average power delivered by the source:

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a

must be 1000 W

b

may be greater than 1000 W

c

may be  equal or less than 1000 W

d

all of the above three are possible

answer is C.

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Detailed Solution

Pav=EvIvcosϕ=100×10 cosϕ=1000 cosϕ Watt
So depending upon value of ϕ, Pav can be equal to or less than 1000 W.

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