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An ac voltage source $V = V_{0} \sin ω t$ is connected across resistance R and capacitance C as shown in figure. It is given that $R = \frac{1}{ω c}$ . The peak current is $I_{0}$ . If the angular frequency of the voltage source is changed to $\frac{ω}{\sqrt{3}}$ keeping R and C fixed, then the new r.m.s current in the circuit is:

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$\frac{I_{0}}{2}$

$\frac{I_{0}}{\sqrt{2}}$

$\frac{I_{0}}{\sqrt{3}}$

$\frac{I_{0}}{3}$

answer is A.

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