Q.

An acid catalysed hydrolysis of ester is carried out in presence of HCl. Small but same volume of samples were taken out at various instant and were titrated with standardised solution of NaOH and following data was obtained

 t=Ot = 120 sec.t = 
VNaOH required for neutralisation20 ml55ml60ml

If initially 6 M of ester was taken then calculate abed, where ab 

ab=t1/2 of the hydrolysis of ester 

cd = Molar concentration of HCl taken in the experiment.

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answer is 4003.

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Detailed Solution

Initially, at t = 0, m mol of HCl = 20 x N, where (N = normality of NaOH) at t = , m mol of HCl + m mol of acid formed = 60 x N 

 m mol of acid formed = 60 x N - 20 x N = 40 N 

 m mol of ester taken =40Na

At t == 120 sec, m mol of acid formed =55×N20×N

=35Nx

ax5Nk×t=lnaaxk×120=ln40N5Nk×120=3ln2t1/2=40

Also, N1v1=N2v2

6×v1=40×N

For HCl,

N×v1=20×N=3v1N=3

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