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Q.

An acidic buffer solution contains 0.01M weak acid HA and 0.1M salt NaA. PKa of weak acid HA is 4. What volume of HA is added to 200ml of 0.1M NaA such that PH of buffer solution is 4.6990.

(antilog of 0.6990 = 5)

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a

200 ml

b

40 ml

c

400 ml

d

20 ml

answer is A.

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Detailed Solution

PH=PKa+logNsVsNaVa

4.6990 = 4 + log200×0.1Va×0.01

0.6990 = log2000Vacid

Vacid = 400 ml

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