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An acidic buffer solution contains 0.01M weak acid HA and 0.1M salt NaA. P^K_^a of weak acid HA is 4. What volume of HA is added to 200ml of 0.1M NaA such that P^H of buffer solution is 4.6990.
(antilog of 0.6990 = 5)

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400 ml

200 ml

20 ml

40 ml

answer is A.

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Detailed Solution

$P^{H} = P^{K_{a}} + \log \frac{N_{s} V_{s}}{N_{a} V_{a}}$

4.6990 = 4 + $\log \frac{200 \times 0.1}{V_{a} \times 0.01}$

0.6990 = log $\frac{2000}{V_{acid}}$

V_acid = 400 ml

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