An acyclic hydrocarbon has molecular formula $C_{4} H_{4}$ as well as it contains a triple and a double bond. The hybridisation of carbon atoms in C-C single bond is

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$s p^{3} - s p^{3}$

$s p^{2} - s p^{2}$

$s p - s p^{3}$

$s p - s p^{2}$

answer is D.

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Detailed Solution

Triple bond is sp and double bond is sp2.

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