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Q.

An adiabatic cylinder has 8 gram of helium in it at 400 K and its piston of area 1cm2(which has mass 1 kg) is movable. If a block of mass 62 kg is placed on the piston then the final temperature of the gas will be n×100K find the value of n (Take atmospheric pressure to be 105Nm2 and g=10m/s2 )

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answer is 16.

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Detailed Solution

P1=P0=105Pa+1×10104=2×105Pa  ;  P2=P0+MgA =105+63×10104=64×105Pa

For adiabatic process T1γP1γ1=T2γP2γ1, 400532×10523=T25364×10523

T2=4003225=400×22=1600K

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