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An aero plane is flying in horizontal direction with a velocity of 600 km/h and at a height of 1960 m. When it is vertically above a point $A$ on the ground a body is dropped from it, the body strikes on the ground at point $B$ . Then, the distance $A B$ will be

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3.33 km

4.33 km

5.33 km

6.33 km

answer is A.

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Detailed Solution

$t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 1960}{9.8}} = 20$ s

$∴$ Horizontal distance $= 600 \times \frac{20}{60 \times 60}$ km $= 3.33$ km

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