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An aeroplane in which the distance between the tips of its wings is 20 m is flying horizontally with a speed of 720kmph over a place where the vertical component of earth’s magnetic field is $2 \times 10^{- 4} W b / m^{2}$ . The induced P.d between the tips of wings will be

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0.8 V

8 V

2.88 V

16 V

answer is D.

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Detailed Solution

$e = B L V = 2 \times 10^{- 4} \times 20 \times 200 = 0.8 V (V = 720 k m p h = 720 \times \frac{5}{18} = 200 m / s)$

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