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An aeroplane in which the distance between the tips of its wings is 20 m is flying horizontaly with a speed to 720kmph over a place where the vertical component of earth’s magnetic field is $2 \times 10^{- 4} W b / m^{2}$ . The induced p.d between the tips of it wings will be

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2.88 v

8 v

16 v

0.8 v

answer is D.

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Detailed Solution

$e = B_{v} l ϑ$
$e = 2 \times 10^{- 4} \times 20 \times 720 \times \frac{5}{18} = 0.8 V$

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