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Q.

An aeroplane is flying horizontally at a height of 980 m with velocity 100 ms^-1 drops a food packet. A person on the ground is 414 m ahead horizontally from the dropping point. At what velocity should he move so that he can catch the food packet.

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a

$50 \sqrt{2} {ms}^{- 1}$

b

$\frac{50}{\sqrt{2}} {ms}^{- 1}$

c

100ms^-1

d

200ms^-1

answer is A.

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Detailed Solution

$T = \sqrt{\frac{2 h}{g}}, R = u \sqrt{\frac{2 h}{g}} = 1414 m$

$Remaining distance = R - 414; v = \frac{R - 414}{T}$ = $50 \sqrt{2} m / s$

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An aeroplane is flying horizontally at a height of 980 m with velocity 100 ms-1 drops a food packet. A person on the ground is 414 m ahead horizontally from the dropping point. At what velocity should he move so that he can catch the food packet.