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An aeroplane is flying horizontally with a velocity of 360 1 km h^-1 . The distance between the tips of the wings of the aeroplane is 50m. The vertical component of the earth’s magnetic field is $4 \times 10^{- 4} {Wbm}^{- 2}$ .The induced emf is

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200 V

20 V

2 V

0.2 V

answer is C.

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Detailed Solution

$\begin{array}{l} e = B_{v} vl \\ e = 4 X 10^{- 4} X 360 X \frac{5}{18} X 50 \\ e = 2 v \end{array}$

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