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Q.

An aeroplane moving horizontally with a speed of 720 kmh-1 drops a food pocket, while flying at a height of 396.9 m. The time taken by a food pocket to reach the ground and its horizontal range is 

(Take 9 = 9.8 ms-2)

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a

 5 s and 500 m

b

8 s and 1500 m

c

9 s and 1800 m

d

3 s and 2000 m

answer is D.

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Detailed Solution

detailed_solution_thumbnail

T=2hg=2×396.99.8=9 s

and u = 720km/h = 200 m/s

∴    R = u x T = 200 x 9 = 1800 m

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