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An aeroplane requires a speed of 72kmph for a take off with 150m run on the ground. The mass of the plane is 1500kg and the coefficient of friction between the aeroplane and the ground is 0.4. Assuming that the aeroplane acceleration uniformly during take off, find the minimum force exerted by the engine of the aeroplane for take off.

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8500 N

9000 N

6500 N

7880 N

answer is B.

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Detailed Solution

For the aeroplane to take off, it needs 72Kmph at the end of 150m.

$∴$ required uniform acceleration would be

2as = v - u

$\Rightarrow 2 a (150 m) = (72 {(\frac{1000}{3600}) m / s)}^{2} - 0^{2}$

$\Rightarrow a = 4 / 3 m / s^{2}$

F_f-F = ma

$\Rightarrow μmg - ma = F_{engine}$

$\Rightarrow F_{engine} = 1500 (0.4 \times 10 - 1.33) \Rightarrow F_{engine} = 7880 N$

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